Question

Write the negative (additive inverse) of each of the following:

(iii)$\frac{-16}{13}$

Answer 1

We know that,
The negative or additive inverse of rational number $\frac{a}{b}$ is $-\frac{a}{b}$ such that $\frac{a}{b}+(-\frac{a}{b})=0$

$\therefore$ Negative of $\frac{-16}{13}=-\left(\frac{-16}{13}\right)$
$=\frac{16}{13}$

Hence, the negative of $\frac{-16}{13}$ is $\frac{16}{13}$.