Write the next two terms of $A . P . 4, 1, - 2, - 5, . . . . .$

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Solution

First term= 4
so $a = 4$
$d$ = $a_{2} - a_{1}$
Let the series be $a_{1}, a_{2}, a_{3}, a_{4}, a_{5}$
$a_{5} = a_{4} + d = - 5 + (- 3) = - 8$
$a_{6} = a_{5} + d = - 8 + (- 3) = - 11$
next two terms of this A.P. will be $- 8, - 11$

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Write the next two terms of A.P.4,1,−2,−5,.....

First term= 4 so a=4 d = a2−a1 Let the series be a1,a2,a3,a4,a5 a5=a4+d=−5+(−3)=−8 a6=a5+d=−8+(−3)=−11 next two terms of this A.P. will be −8,−11

Write the next two terms of $A . P . 4, 1, - 2, - 5, . . . . .$

First term= 4
so $a = 4$
$d$ = $a_{2} - a_{1}$
Let the series be $a_{1}, a_{2}, a_{3}, a_{4}, a_{5}$
$a_{5} = a_{4} + d = - 5 + (- 3) = - 8$
$a_{6} = a_{5} + d = - 8 + (- 3) = - 11$
next two terms of this A.P. will be $- 8, - 11$