Question

Write the number of electrons present in the outermost shells of the following elements:
Lithium, carbon, oxygen, and sodium.

[2 Marks]

Answer 1

Lithium:
Atomic number = 3.
The electronic configuration = 2, 1.
So, 1 electron is present in the outermost shell.
[0.5 Marks]
Carbon:
Atomic number = 6.
The electronic configuration = 2, 4.
So, 4 electrons are present in the outermost shell.
[0.5 Marks]
Oxygen:
Atomic number = 8.
The electronic configuration = 2, 6.
So, 6 electrons are present in the outermost shell.
[0.5 Marks]
Sodium:
Atomic number = 11.
The electronic configuration = 2, 8, 1.
So, 1 electron is present in the outermost shell.
[0.5 Marks]