Write the number of real roots of the equation (x−1)2+(x−2)2+(x−3)2=0
(x−1)2+(x−2)2+(x−3)2=0⇒x2−2x+1+x2−4x+4+x2−6x+9=0⇒3x2−12x+14=0Now, D=b2−4ac=(−12)2−4.3.14−144−168=−24<0∵D < 0 so, no real roots