Write the number of terms in the expansion of ${[{(2 x + y^{3})}^{4}]}^{7}$ .

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Solution

In the binomial expansion of ${(a + b)}^{n}$ , total number of terms will be (n + 1).

Now, ${[{(2 x + y^{3})}^{4}]}^{7} = {(2 x + y^{3})}^{28}$

Therefore, in the expansion of ${[{(2 x + y^{3})}^{4}]}^{7}$ , total number of terms will be 28 + 1 = 29.

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