CameraIcon

SearchIcon

MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Order of Magnitude

Write the ord...

Question

Write the order of magnitude of mass of an electron $9.1 \times 10^{- 31}$ kg.

Open in App

Solution

If mass of an electron is $9.11 X 10^{- 31} k g = 9.11 X 10^{- 28} g$

$1 k g = 1000 g$

Electrons in one kg would be = $\frac{1000}{9.11 X 10^{- 28}}$

= $\frac{1000}{9.11} X 10^{- 28}$

= $109.76 X 10^{28}$

= $1.0976 X 10^{30}$

= $10^{30}$

Suggest Corrections

thumbs-up

0

Similar questions

Q. The mass of the electron is given

9.1 \times 10^{- 31} k g

. Find the order of magnitude of the number of electrons of

1 k g

.

Q. In the oil drop experimant, charge on electron came out to be

- 1.6 \times 10^{- 19} C

. From Thomson's experiment,

e / m

value for electron calculated was

1.758820 \times 10^{11} C/kg

. Find the mass of the electron.
(Given:

e

is the magnitude of charge on electron)

Q. The kinetic energy of an electron is

4.55 \times 10^{- 25} J

.The mass of electron is

9.1 x 10^{- 31} kg

.The velocity of the electron is .

(m a s s = 9.1 \times 10^{- 31} k g)

is sent into an electric field of intensity

9.1 \times 10^{6}

N/C. The acceleration produced is

Q. Calculate the wavelength of an electron if its kinetic energy is

3.0 \times 10^{- 25} J

. Mass of an electron is

9.1 \times 10^{- 31} K g

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Significant Figures

PHYSICS

Watch in App

explore_more_icon

Explore more

Order of Magnitude

Standard XII Physics

Join BYJU'S Learning Program

CrossIcon