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Question

Write the order of the differential equation :
log(d2ydx2)=(dydx)3+x

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Solution

Given log(d2ydx2)=(dydx)3+x
log(d2ydx2)(dydx)3+(x)=0
log(d2ydx2)(dydx)3x=0
logy11(y)3x=0
Highest order of dervitative =2
order =2.

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