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Question

Write the position vector of a point dividing the line segment joining points having position vectors i^+j^-2k^ and 2i^-j^+3k^ externally in the ratio 2:3.

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Solution

Let A and B be the points with position vectors a=i^+j^-2k^ , b=2i^-j^+3k^ respectively.
Let C divide AB externally in the ratio 2 : 3 such that AC : CB = 2 : 3
∴ Position vector of C = 22i^-j^+3k^-3i^+j^-2k^2-3
= 4i^-2j^+6k^-3i^-3j^+6k^-1
= i^-5j^+12k^-1
= -i^+5j^-12k^

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