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Byju's Answer
Standard XII
Mathematics
Domain and Range of Basic Inverse Trigonometric Functions
Write the pri...
Question
Write the principal value of
cos
−
1
(
1
2
)
−
2
sin
−
1
(
−
1
2
)
.
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Solution
We have;
cos
−
1
(
1
2
)
−
2
sin
−
1
(
−
1
2
)
=
cos
−
1
(
1
2
)
+
2
sin
−
1
(
−
1
2
)
[
∴
sin
−
1
(
−
x
)
=
−
sin
−
1
x
;
x
ϵ
[
−
1
,
1
]
]
=
π
2
+
sin
−
1
(
1
2
)
[
∴
sin
−
1
+
cos
−
1
x
=
π
2
x
ϵ
[
−
1
,
1
]
]
=
π
2
+
(
2
n
π
+
π
6
)
=
2
n
π
+
2
π
3
Hence, principal value of
cos
−
1
(
1
2
)
−
2
sin
−
1
(
−
1
2
)
=
2
n
π
+
2
π
3
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