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Byju's Answer
Standard XII
Mathematics
Differentiation Using Substitution
Write.the pri...
Question
Write.the principal value of
tan
-
1
1
+
cos
-
1
-
1
2
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Solution
tan
-
1
1
+
cos
-
1
-
1
2
=
tan
-
1
tan
π
4
+
cos
-
1
cos
2
π
3
=
π
4
+
2
π
3
=
11
π
12
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Similar questions
Q.
Write the principal value of
t
a
n
−
1
(
1
)
+
c
o
s
−
1
(
−
1
2
)
Q.
For the principal values, evaluate each of the following:
i
tan
-
1
(
-
1
)
+
cos
-
1
-
1
2
(ii)
tan
-
1
2
sin
4
cos
-
1
3
2
Q.
Inverse circular functions,Principal values of
s
i
n
−
1
x
,
c
o
s
−
1
x
,
t
a
n
−
1
x
.
t
a
n
−
1
x
+
t
a
n
−
1
y
=
t
a
n
−
1
x
+
y
1
−
x
y
,
x
y
<
1
π
+
t
a
n
−
1
x
+
y
1
−
x
y
,
x
y
>
1
.
(a)
t
a
n
−
1
1
21
+
t
a
n
−
1
1
13
+
t
a
n
−
1
(
−
1
8
)
=
0
(b)
t
a
n
−
1
2
3
=
1
2
t
a
n
−
1
12
5
(c)
t
a
n
−
1
1
4
+
t
a
n
−
1
2
9
=
1
2
c
o
s
−
1
3
5
.
Q.
Inverse circular functions,Principal values of
s
i
n
−
1
x
,
c
o
s
−
1
x
,
t
a
n
−
1
x
.
t
a
n
−
1
x
+
t
a
n
−
1
y
=
t
a
n
−
1
x
+
y
1
−
x
y
,
x
y
<
1
π
+
t
a
n
−
1
x
+
y
1
−
x
y
,
x
y
>
1
.
(a)
s
i
n
(
2
t
a
n
−
1
1
3
)
+
c
o
s
(
t
a
n
−
1
2
√
2
)
=
14
15
(b) Prove that
s
i
n
−
1
{
c
o
t
(
s
i
n
−
1
√
(
2
−
√
3
4
)
+
c
o
s
−
1
√
12
4
+
s
e
c
−
1
√
2
)
}
=
0
Q.
cos
−
1
(
cos
(
−
5
)
)
+
sin
−
1
(
sin
(
6
)
)
−
tan
−
1
(
tan
(
12
)
)
is equal to
(The inverse trigonometric functions take the principal values)
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