Write the product and mechanism for given reactions.
$C_{6} H_{5} - C H_{2} - C H O D i l N a O H - ----- \to (D)$

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Solution

$C_{6} H_{5} - C H_{2} - C H O d i l . N a O H - ------- \to$
aldehydes in presence of dil NaOH undergo aldol condensation C only $R - C H_{2} - C (= O) - H$ kind)

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Similar questions

C_{6} H_{5} - C H_{2} C O_{2} C H_{3} 1. C H_{3} M g B r (e x c e s s) - ------------ \to 2. H_{2} O

C_{6} H_{5} - C H_{2} - C l

C_{6} H_{5} - C H_{2} - C H_{2} - N H_{2}

C_{6} H_{5} - O | | C - C H_{2} I

(i) O H^{-} - ---- \to (i i) H_{3} 0^{+}

C_{6} H_{5} - C H_{2} - C H_{2} - O | | C - C H_{2} I

(i) N a O H a n d I_{2} - --------- \to (i i) H_{3} O^{+}

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Q

Draw the resonance structures for the following compounds. Show the electron shift using curved-arrow notation.

(a) C₆H₅OH (b) C₆H₅NO₂ (c) CH₃CH = CH – CHO

(d) C₆H₅CHO (e) (f)

C H_{3} - C H_{2} - C I

C H_{3} - C H_{2} - C H_{2} - N H_{2}

C_{6} H_{5} - C H_{2} - C I

C_{6} H_{5} - C H_{2} - C H_{2} - N H_{2}

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