Write the product obtained by following reaction.
$C r_{2} O_{7}^{2 -} (a q) + I^{-} (a q) + H^{+} \to$ ?

Open in App

Solution

$C r_{2} O_{7}^{2 -} + I^{-} + 8 H^{+} \to I O_{3}^{-} + 2 C r^{3 +} + 4 H_{2} O$

Suggest Corrections

Similar questions

S_{2} O {_{6}}^{2 -} (a q) + C r_{2} O {_{7}}^{2 -} (a q) \to S_{4} O {_{6}}^{2 -} (a q) + C r^{3 +} (a q)

B i (O H)_{3} ↓ + [S n (O H)_{4}]^{2 -} (a q) ⟶ P r o d u c t s

B i^{3 +} (a q) + I^{-} (a q) (n o t i n e x c e s s) ⟶ P r o d u c t s

A g^{+} (a q) + H_{2} S (g) H^{+} - - \to P r o d u c t s

[B i I_{4}]^{-} (a q) + H_{2} O (l) D i l u t i o n - ---- \to P r o d u c t s

Balance the following redox reactions by ion-electron method:

(a) (aq) + I^– (aq) → MnO₂ (s) + I₂(s) (in basic medium)

(b) (aq) + SO₂ (g) → Mn²⁺ (aq) + (aq) (in acidic solution)

(d) + SO₂(g) → Cr³⁺ (aq) + (aq) (in acidic solution)

The oxidation half reaction for following reaction is

Fe²⁺(aq) + Cr₂O₇^2-(aq) → Fe³⁺ (aq) + Cr³⁺(aq)

H^{+}

S_{2} O_{3}^{2 -} (a q) + C r_{2} O_{7}^{2 -} (a q) \to S_{4} O_{6}^{2 -} (a q) + C r^{3 +} (a q)

Join BYJU'S Learning Program