Question

Write the proper number in the empty boxes.
(1) $\frac{3}{5}=\frac{3\times \boxed{x}}{5\times \boxed{x}}=\frac{\boxed{x}}{10}=\boxed{x}$

(2) $\frac{{\displaystyle 25}}{{\displaystyle 8}}=\frac{{\displaystyle 25\times \boxed{x}}}{{\displaystyle 8\times 125}}=\frac{{\displaystyle \boxed{x}}}{{\displaystyle 1000}}=3.125$

(3) $\frac{{\displaystyle 21}}{{\displaystyle 2}}=\frac{{\displaystyle 21\times \boxed{x}}}{{\displaystyle 2\times \boxed{x}}}=\frac{{\displaystyle \boxed{x}}}{{\displaystyle 10}}=\boxed{x}$

(4) $\frac{{\displaystyle 22}}{{\displaystyle 40}}=\frac{11}{20}=\frac{{\displaystyle 11\times \boxed{x}}}{{\displaystyle 20\times 5}}=\frac{{\displaystyle \boxed{x}}}{{\displaystyle 100}}=\boxed{x}$

Answer 1

(1) $\frac{3}{5}=\frac{3\times \boxed{2}}{5\times \boxed{2}}=\frac{\boxed{6}}{10}=\boxed{0.6}$

(2) $\frac{{\displaystyle 25}}{{\displaystyle 8}}=\frac{{\displaystyle 25\times \boxed{125}}}{{\displaystyle 8\times 125}}=\frac{{\displaystyle \boxed{3125}}}{{\displaystyle 1000}}=3.125$

(3) $\frac{{\displaystyle 21}}{{\displaystyle 2}}=\frac{{\displaystyle 21\times \boxed{5}}}{{\displaystyle 2\times \boxed{5}}}=\frac{{\displaystyle \boxed{105}}}{{\displaystyle 10}}=\boxed{10.5}$

(4) $\frac{{\displaystyle 22}}{{\displaystyle 40}}=\frac{11}{20}=\frac{{\displaystyle 11\times \boxed{5}}}{{\displaystyle 20\times 5}}=\frac{{\displaystyle \boxed{55}}}{{\displaystyle 100}}=\boxed{0.55}$