Write the rationalising factor for 6/√12-√3.
We know that (a+b)(a−b)=a2−b2
Now, if an expression of the form (a√b-c√d) is given, we can rationalise that expression by multiplying it with (a√b+c√d) since
(a√b+c√d)(a√b−c√d)=a2b−c2d
Thus, to rationalise 6/√12-√3(, we multiply it with
The6/√12+√3 expression that is multiplied with an irrational expression to obtain a rational number is called the "rationalising factor".