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Question

Write the rationalising factor for 6/√12-√3.

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Solution

We know that (a+b)(ab)=a2b2
Now, if an expression of the form (ab-cd) is given, we can rationalise that expression by multiplying it with (ab+cd) since
(ab+cd)(abcd)=a2bc2d
Thus, to rationalise 6/√12-√3(, we multiply it with
The6/√12+√3 expression that is multiplied with an irrational expression to obtain a rational number is called the "rationalising factor".


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