Write the reaction involved in lead storage battery.

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Solution

The lead storage battery is a rechargeable battery. Thus there are two sets of reaction involved in the lead storage battery.
Reaction involved in lead stroage battery when it is used are as follow:
Anode: $P b (s) + S O_{4}^{2 -} (a q) \to P b S O_{4} (s) + 2 e^{-}$
Cathode: $P b O_{2} (s) + 4 H^{+} (a q) + S O_{4}^{2 -} (a q) + 2 e^{-} \to P b S O_{4} (s) + 2 H_{2} O (l)$
Thus, overall cell reaction can be given as follow:
$P b (s) + P b O_{2} (s) + 4 H^{+} (a q) + 2 S O_{4}^{2 -} (a q) \to 2 P b S O_{4} (s) + 2 H_{2} O (l)$
Reaction involved during the recharging of the battery:
Anode: $P b S O_{4} (s) + 2 H_{2} O (l) \to P b O_{2} (s) + 4 H^{+} (a q) + 2 S O_{4}^{2 -} (a q) + 2 e^{-}$
Cathode: $P b S O_{4} (s) + 2 e^{-} \to P b (s) + S O_{4}^{2 -} (a q)$

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Similar questions

Write the chemistry of recharging the lead storage battery, highlighting all the materials that are involved during recharging.

Z n (s) + A g_{2} O (s) + H_{2} O (l) \to Z N^{2 +} (a q) + 2 (A g (s) + 2 O H^{-} (a q)

E^{o}

Δ G^{o}

E_{A g^{+} / A g}^{o} = + 0.80 V, E_{Z n^{2 +} / Z n}^{o} = - 0.76 V)

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