Write the relation for binding energy (B.E) (in MeV) of a nucleus of mass AZM, atomic number (Z) and mass number (A) in terms of the masses of its constituents - neutrons and protons.
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Solution
The binding energy in (MeV) is EB=(Zmp+Nmn−MZA)c2 Where mp= mass of proton , mn= mass of neutron, c=velocity of light. Now N=A−Z thus, EB=[Zmp+(A−Z)mn−MZA]c2=[Z(mp−mn)+Amn−MZA)c2