Write the set A={1,1/8,1/27,1/64,1/125} in set builder form

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Solution

Notation: x€A means x belongs to A

As you see, 1, 8, 27, 64 and 125 are perfect cubes.

So, set A can be written as:

A = {1/x^3 ; x€N, x≤5 }

Where N is the set of natural numbers.

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Similar questions

Y = {1, \frac{1}{8}, \frac{1}{27}, \frac{1}{64}, \frac{1}{125}}

A = {1 + \frac{1}{8}, \frac{1}{27}, \frac{1}{64}, \frac{1}{125}}

A = {2, 3, 6}

P (A)

The set-builder form of the set $A = {\frac{1}{2}, \frac{1}{4}, \frac{1}{8}, \frac{1}{16}, \frac{1}{32}, \frac{1}{64}}$ is ___.

A = {- 1, 1}

The set-builder form of the set ${\frac{1}{2}, \frac{1}{4}, \frac{1}{8}, \frac{1}{16}, \frac{1}{32}, \frac{1}{64}}$ is

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