Write the smallest $6$ -digit number that can be formed if only one digit is allowed to appear twice.

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Solution

Step 1: Write the first $5$ smallest digits(one less than the required no. of digits in the number) in ascending order.
The first five $5$ smallest digits in ascending order-- $0 < 1 < 2 < 3 < 4$
Step 2: To form the smallest $6$ -digit number using only one digit twice.
To form the smallest $6$ -digit number using only one digit twice, we have to write the number using the $5$ -digits in above order and repeating the smallest digit, i.e., $0$ twice.
Since, we cannot place $0$ at the extreme left(or the highest place), substitute it with the digit on its immediate right . So, the smallest $5$ -digit number is $1, 00, 234$
Hence, the smallest $6$ -digit number that can be formed if only one digit is allowed to appear twice is $1, 00, 234$

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Write the smallest 6-digit number that can be formed if only one digit is allowed to appear twice.

Write the smallest $6$ -digit number that can be formed if only one digit is allowed to appear twice.