Question

Write the smallest digit and the greatest digit in the blank space of $4765\_\_2$, so that the number is divisible by $3$.

Answer 1

Step $1:$ Finding the smallest digit:

Divisibility of $3$: A number is divisible by $3$, when the sum of the digits of the number is divisible by $3$

The given number is $4765\_\_2$

Sum of the given digits $4+7+6+5+2=24$

$24$ is divisible by $3$

Therefore, the smallest digit is $24$$-$$24$$=$$0$

Step $2:$ Finding the greatest digit:

Now, for greatest digit, the sum should be greatest and divisible by $3$

Therefore, the greatest sum is $33$

Thus, the greatest digit is $33$$-$$24$$=$$9$

Hence, the smallest digit is $0$ and the greatest digit is $9$.