Question

Write the smallest digit in the blank space of the given number $5_{}\_,945$ so that the number formed is divisible by $3$.

Answer 1

We know that A number is divisible by $3$, if the sum of the digits of the given number is divisible by $3$.

Here, adding the digits of the given number we get $5+9+4+5=23$. But if we add $1$ to the given number, then the sum of the digits formed will be $24$ which is divisible by $3$.

Therefore, the smallest digit in the blank space will be $1$.