Write the solution of the pair of linear equations $3 x + 4 y = 0$ and $2 x - y = 0$

Open in App

Solution

$3 x + 4 y = 0 . . . . . . . . . . . (i)$
$2 x - y = 0 . . . . . . . . . . . . (i i)$

Substituting value of $y$ from (ii) in (i), we get:
$3 x + 4 \times (2 x) = 0$
$x = 0$
Substituting value of $x$ in (ii), we get:
$y = 2 \times 0 = 0$

Hence, the solution to the given pair of linear equations is $(0, 0)$

Suggest Corrections

Similar questions

The number of solutions of the pair of linear equations x + 2y - 8 = 0 and 2x + 4y = 16 are:

2 x + 3 y = 0

3 x + 4 y = 5

Solution for the following pair of linear equations is:
2x + 4y = 8
4x + 8y = 0

3 x - 5 y + 1 = 0, 2 x - y + 3 = 0

x = x_{1}, y = y_{1}

y_{1} =

x + y = 5, 2 x + 2 y = 10

x - y = 8, 3 x - 3 y = 16

2 x + y - 6 = 0, 4 x - 2 y - 4 = 0

2 x - 2 y - 2 = 0, 4 x - 4 y - 5 = 0

Join BYJU'S Learning Program