Write the structure of the following organic halogen compound. $2 - (2 - chlorophenyl) - 1 - iodooctane$

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Solution

IUPAC rule:
IUPAC is the International Union for Pure and Applied Chemistry.
It is a worldwide using chemical names that follow certain rules.
Structure:
Step 1: Finding the longest chain and number of carbon atom
Here, there is eight carbon which is arranged linearly.
$C - C - C - C - C - C - C - C$
Step 2: Finding and positioning substituents.
$2 - (2 - chlorophenyl)$ indicates the phenyl group is attached to the second position of the carbon chain and the chloro group is attached to the second carbon of the phenyl ring.
In the $C_{6} H_{5} Cl$ group, the chloro group is attached at the second position to the phenyl group.
$C - \underset{|}{C} - C - C - C - C - C - C C_{6} H_{5} {Cl}^{}$
$1 -$ Iodo octane indicates the iodine group is attached to the first carbon.
$I - C - \underset{|}{C} - C - C - C - C - C - C \underset{}{C_{6} H_{5} Cl}$
Step 3: Satisfying the valency of carbon.
On satisfying the valency of carbon with hydrogen the structure of the compound will be

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4 -

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4 -

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