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Question

Write the structures of the following organic halogen compound.

A 2-Chloro-3- methylpentane

B p-Bromochlorobenzene

C 1-Chloro-4-ethylcyclohexane

D 2-(2-Chlorophenyl)-1-iodooctane

E 2-Bromobutane

F 4-tert-Butyl-3-iodoheptane

G 1-Bromo-4-sec-butyl-2-methylbenzene

H 1,4-Dibromobut-2-ene

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Solution

Name: 2−Chloro−3−methylpentane
Word root: pent (there are 5 carbons in main chain)
Suffix: ane (there are only single bonds)

The substituents are as follows:
C2: chloro
C3: methyl

Hence, the structure of the compound
(2−Chloro−3−methylpentane) can be shown as -



Name: p-Bromochlorobenzene
There is benzene ring as the main chain.

The substituents are as follows:
C1: bromo
C4: chloro

Hence, the structure of the compound (p-Bromochlorobenzene) can be shown as -



Name: 1-Chloro-4-ethylcyclohexane
Word root: hex(there are 6 carbons in
main chain, prefix ‘cyclo’ shows that it
is a cyclic structure).
Suffix: ane(there are only single bonds)

The substituents are as follows:
C1: chloro
C4: ethyl

Hence, the structure of the compound
(1-Chloro-4-ethylcyclohexane) can be shown as -



Name: 2-(2-Chlorophenyl)-1-iodooctane
Word root: oct(there are 8 carbons in
main chain)
Suffix: ane(there are only single bonds)

The substituents are as follows:
C1: iodo
C2: (2-Chlorophenyl)

Hence, the structure of the compound
(2-(2-Chlorophenyl)-1-iodooctane)
can be shown as -



Name: 2-Bromobutane
Word root: but(there are 4 carbons in
main chain)
Suffix: ane(there are only single bonds)

The substituent is as follows:
C2: bromo

Hence, the structure of the compound
(2-Bromobutane) can be shown as-



Name: 4-tert-Butyl-3-iodoheptane
Word root: hept (there are 7 carbons in
main chain)
Suffix: ane (there are only single bonds)

The substituents are as follows:
C3: iodo
C4: tert-butyl

Hence, the structure of the compound
(4-tert-Butyl-3-iodoheptane) can be shown
as-



Name: 1-Bromo-4-sec-butyl-2-methylbenzene
Benzene ring is the main chain.

The substituents on the ring are as follows:
C1: bromo
C2: methyl
C4: sec-butyl

Hence, the structure of the compound
(1-Bromo-4-sec-butyl-2-methylbenzene) can
be shown as -



Name: 1,4-Dibromobut-2-ene
Word root: but (there are 4 carbons
in main chain)
Suffix: ene (there is a double bond)

The substituents are as follows:
C1: bromo
C4: bromo

Hence, the structure of the compound (1,4-Dibromobut-2-ene) can be shown as -


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