Question

Write the terms of the series having the generalised formula $(3n+2)$

Answer 1

Finding the term of series

Given algebraic expression is $(3n+2)$

Putting the natural numbers in place of n, we get the terms of the expression

Put $n=1$

$\Rightarrow$ $3\left(1\right)+2=5$ this is the first term

Put $n=2$

$\Rightarrow$ $3\left(2\right)+2=8$

Put $n=3$

$\Rightarrow$ $3\left(3\right)+2=11$

Hence, $5,8,11,14,17$are the terms of the series $(3n+2)$