Question

​​Write the total number of distinct prime factors in the prime factorization of the number 42840.

Answer 1

Dear Student ,

$$\begin{gathered} \mathrm{Prime}\mathrm{factors}\mathrm{of}42840=2^3\times 3^2\times 5\times 7\times 17 \\ \mathrm{Number}\mathrm{of}\mathrm{distinct}\mathrm{prime}\mathrm{factors}\mathrm{are}5. \end{gathered}$$

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