Question

Write the type of reaction :

Sodium hydroxide solution is treated with acetic acid to form sodium acetate and water.

• A. Combination reaction
• B. Neutralization reaction
• C. Decomposition reaction
• D. Displacement reaction

Answer 1

The correct option is B Neutralization reaction

Sodium hydroxide ($NaOH$) reacts with acetic acid ($C{H}_{3}COOH$) to form sodium acetate ($C{H}_{3}COONa$) and water ($H_{2}O$).

The equation for this reaction can be written as :

$NaOH+C{H}_{3}COOH\to C{H}_{3}COONa+H_{2}O$

It is a double displacement reaction as both the reactants exchange ions to form new products.

Also it is a neutralization reaction as the base ($NaOH$) reacts with an acid ($C{H}_{3}COOH$) to form salt ($C{H}_{3}COONa$) and water ($H_{2}O$).

Hence the correct option is B.