Question

Write the value of $\left(1+{\tan }^2\theta \right){\cos }^2\theta$.

Answer 1

$$\begin{gathered} \left(1+{\tan }^2\theta \right){\cos }^2\theta \\ ={\sec }^2\theta \times \frac{1}{{\sec }^2\theta } \\ =1 \end{gathered}$$