Write the value of 2(sinθ+cos6θ)−3(sin4θ+cos4θ)+1.
2(sin6θ+cos6θ)−3(sin4θ+cos4θ)+1
=2((sin3θ)2+(cos3θ)2)−3((sin2θ)2)+(cos2θ)2)+1
=2(1)-3(1)+1
=2-3+1
=0
Use the suitable identity and simplify the given expression.2(sin6θ+cos6θ)−3(sin4θ+cos4θ)+1