Question

Write the value of cos $\left(2{\sin }^{-1}\frac{1}{2}\right)$.

Answer 1

We have, cos $\left(2{\sin }^{-1}\frac{1}{2}\right)$ = $\cos \left(2\times \frac{\mathrm{\pi }}{6}\right)=\cos \left(\frac{\mathrm{\pi }}{3}\right)=\frac{1}{2}$