wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Write the value of π20sinxdx.

Open in App
Solution

π20sinxdx=[cosx]π20=cosπ2+cos0=1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Fundamental Theorem of Calculus
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon