Question

Write the value of $\int \frac{dx}{ax+1}$.

Answer 1

Let $I=\int \frac{dx}{ax+1}$

Also, $t=ax+1$

$\Rightarrow dt=adx$

$\therefore I=\int \frac{dt}{at}=\frac{1}{a}\log t$

$=\frac{1}{a}\times \log (ax+1)$