Write the value of ddx(x|x|).
We have,
ddxx|x|=⎧⎪ ⎪ ⎪⎨⎪ ⎪ ⎪⎩ddxx2 [if x>0]ddx(−x)x [if x<0]
={2x [if x>0]−2x [if x<0]
Write the value of ddx {(x+|x|) |x|}