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Question

Write the value of ddx {(x+|x|) |x|}

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Solution

We have,

ddx {(x+|x|) |x|}

=⎪ ⎪ ⎪⎪ ⎪ ⎪ddx2x2 [if x>0]ddx(x+x)x [if x<0]

={4x [if x>0]0 [if x<0]}


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