Write the value of (12)3+(13)3−(56)3
(12)3+(13)3−(56)3Leta=12,b=13and c=−56∵a+b+c=12+13−56=3+2−56=06=0a3+b3+c3=3abc∴(12)3+(13)3−(−56)=3×12×13×(−56)=−512
Without actually calculating the cubes, find the value of :