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Byju's Answer
Standard XII
Physics
Pulley
Write the val...
Question
Write the value of
sec
−
1
(
1
2
)
.
Open in App
Solution
Given,
sec
−
1
1
2
Let,
sec
−
1
1
2
=
θ
⇒
sec
θ
=
1
2
Range of
sec
−
1
is
[
0
,
π
]
−
{
π
2
}
sec
−
1
1
2
is not in
[
0
,
π
]
−
{
π
2
}
there is no solution
Hence the solution is
ϕ
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