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Byju's Answer
Standard XII
Mathematics
Evaluation of a Determinant
Write the val...
Question
Write the value of the determinant
[
p
p
+
1
p
−
1
p
]
when
p
=
1342
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Solution
We have,
[
p
p
+
1
p
−
1
p
]
=
p
2
−
(
p
+
1
)
(
p
−
1
)
=
p
2
−
(
p
2
−
1
)
=
1
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