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Question

Write the value of the expression
14sin10sin702sin10


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    Solution

    We have,
    14sin10sin702sin10=12(2sin10 sin70)2sin10=12(cos7010)cos(70+10)2sin10=12[cos60cos80]2sin(9010)=12(12cos80)2cos80=1(22+2cos80)2cos80=11+2cos802cos80=1



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