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Question

Write the value of =∣ ∣x+yy+zz+xzxy333∣ ∣.

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Solution

On expansion, we get,
∣ ∣x+yy+zz+xzxy333∣ ∣=(x+y)(3x+3y)(y+z)(3z+3y)+(z+x)(3z+3x)=3(x2y2+y2z2+z2x2)=0

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