CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Write the value of =∣ ∣x+yy+zz+xzxy333∣ ∣.

Open in App
Solution

On expansion, we get,
∣ ∣x+yy+zz+xzxy333∣ ∣=(x+y)(3x+3y)(y+z)(3z+3y)+(z+x)(3z+3x)=3(x2y2+y2z2+z2x2)=0

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon