Write the zeroes of the polynomial x2+2x+1.
Find the zeroes of the polynomial
Let p(x)=x2+2x+1,
p(x)=x2+2x+1=x2+x+x+1=x(x+1)+1(x+1)=(x+1)(x+1)
The value of the polynomial p(x)=0
⇒(x+1)(x+1)=0⇒(x+1)=0,(x+1)=0⇒x=-1,x=-1
Hence, the polynomial p(x)= x2+2x+1has repeated zeroes-1.
If one zero of the polynomial x2−4x+1 is (2+√3) , write the other zero.