Write the zeros of the polynomial $x^{2} - x - 6$ .

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Solution

$x^{2} - x - 6 = 0$

$x^{2} - 3 x + 2 x - 6 = 0$

$x (x - 3) + 2 (x - 3) = 0$

$(x + 2) (x - 3) = 0$

So -2 and 3 are the zeros of the given polynomial

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Write the zeros of the polynomial x2−x−6.

x2−x−6=0 x2−3x+2x−6=0 x(x−3)+2(x−3)=0 (x+2)(x−3)=0 So -2 and 3 are the zeros of the given polynomial

Write the zeros of the polynomial $x^{2} - x - 6$ .

$x^{2} - x - 6 = 0$

$x^{2} - 3 x + 2 x - 6 = 0$

$x (x - 3) + 2 (x - 3) = 0$

$(x + 2) (x - 3) = 0$

So -2 and 3 are the zeros of the given polynomial