Write the zeros of the polynomial $x^{2} - x - 6$ .

Open in App

Solution

$x^{2} - x - 6 = 0$

$x^{2} - 3 x + 2 x - 6 = 0$

$x (x - 3) + 2 (x - 3) = 0$

$(x + 2) (x - 3) = 0$

So -2 and 3 are the zeros of the given polynomial

Suggest Corrections

112

Similar questions

Q. Write the zeros of the quadratic polynomial f(x) = 6x² − 3

Verify that
(i) 1 and 2 are the zeros of the polynomial, $p (x) = x^{2} - 3 x + 2$ .
(ii) 2 and -3 are the zeros of the polynomial, $q (x) = x^{2} + x - 6.$
(iii) 0 and 3 are the zeros of the polynomial, $r (x) = x^{2} - 3 x$ .

write the zeroes of the polynomial x²-x-6

Q. The zeros of the polynomial p(x) = x² + x – 6 are
(a) 2, 3
(b) –2, 3
(c) 2, –3
(d) –2, –3

Q. Find the zeros of the polynomial

6 + x^{2} - 5 x

Join BYJU'S Learning Program

Write the zeros of the polynomial x2−x−6.

x2−x−6=0 x2−3x+2x−6=0 x(x−3)+2(x−3)=0 (x+2)(x−3)=0 So -2 and 3 are the zeros of the given polynomial

Write the zeros of the polynomial $x^{2} - x - 6$ .

$x^{2} - x - 6 = 0$

$x^{2} - 3 x + 2 x - 6 = 0$

$x (x - 3) + 2 (x - 3) = 0$

$(x + 2) (x - 3) = 0$

So -2 and 3 are the zeros of the given polynomial