Question

Write two solution of $3x+4y=7,x=6y$.

Answer 1

$3x+4y=7$

$3x=7-4y$

when $x=1,4y=4$

$\Rightarrow y=1$

$\therefore (1,1)$ is a solution

when $x=3,y=\frac{1}{4}$

$\therefore (2,\frac{1}{4})$ is a solution

$\therefore (1,1)$ and $(2,\frac{1}{4})$ are $2$ solutions.