Writhe the following sets in roster (Tabular) form:

(ii) $A_{2} = {x : x^{2} - 4 x - 5 = 0}$

Open in App

Solution

Step : Express the given set in roster (Tabular) form:

We know that in roster or tabular method, the elements of the set are written inside a pair of curly braces and are separated by commas.

Given :

$A_{2} = {x : x^{2} - 4 x - 5 = 0}$

$\Rightarrow x^{2} - 4 x - 5 = 0$

$\Rightarrow x^{2} - 5 x + x - 5 = 0$

$[- 5 x + x = - 4 x]$

$\Rightarrow x (x - 5) + 1 (x - 5) = 0$

$\Rightarrow (x + 1) (x - 5) = 0$

$\Rightarrow x = - 1 o r 5$

Hence, the set $A_{2} = {x : x^{2} - 4 x - 5 = 0}$ in roster (Tabular) form is $A_{2} = {- 1, 5} .$

Suggest Corrections

Similar questions

Represent the given sets in roster form $A_{2}$ = { $x$ : $x^{2} - 4 x - 5 = 0}$

{x \in N : x^{2} < 25}

$A_{5} =$

${x : x = 4 n, n \in W a n d n < 4}$

A_{1} = {x : 2 x + 3 = 11}

$A_{6} = {x : x = \frac{n}{n + 2}; n$

$\in N a n d n > 5}$

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program