Written:

Construct a triangle PQR, in which PQ = 6.7 cm, QR = PR = 5.4 cm.

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Solution

Construction of ΔPQR, where PQ = 6.7 cm, QR = PR = 5.4 cm.

Steps of construction:

(i) Draw PQ = 6.7 cm.

(ii) Using the compass, with P and Q as centers and radii as 5.4 cm, draw arcs which cut each other at point R.

Here, ΔPQR is the required triangle.

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Construct a triangle PQR in which PQ + PR = 6.5 cm, QR = 5.4 cm and ∠Q = 40°.

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Construct a triangle PQR, in which PQ = QR = RP = 6 cm.

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Construct a triangle PQR in which PQ = 5.4 cm, QR = 5.5 cm and ∠PQR = 55°.

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