Question

x-1/7x-14 = x-3\7x-26
sir plz explain me properly

Answer 1

$\frac{x-1}{7x-14}$= $\frac{x-3}{7x-26}$ We cross-multiply to get
(x-1)(7x-26)= (x-3)(7x-14)
$7x^2$-7x-26x+26= $7x^2$-21x-14x+42
$7x^2$-33x+26 = $7x^2$-35x+42 Bring all terms to left
$7x^2$-33x+26-$7x^2$+35x-42= 0
2x-16 = 0
2x= 16
x= 8