X-1 is a factor of px-x3-3 x2-3 x-1- so what is the value of p-1

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Factorisation of a Polynomial

x+1 is a fact...

Question

x+1 is a factor of p(x)= x³+3x²+3x+1 , so what is the value of p(-1)

-1

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g (x)

p (x)

p (x) = 2 x^{3} + x^{2} - 2 x - 1, g (x) = x + 1

p (x) = x^{3} + 3 x^{2} + 3 x + 1, g (x) = x + 2

p (x) = x^{3} - 4 x^{2} + x + 6, g (x) = x - 3

(i) p (x) = 2 x^{3} + x^{2} - 2 x - 1, g (x) = x + 1

(i i) p (x) = x^{3} + 3 x^{2} + 3 x + 1, g (x) = x + 2

(i i i) p (x) = x^{3} - 4 x^{2} + x + 6, g (x) = x - 3

p

(x + 3)

x^{3} - 3 x^{2} - p x + 24

Use the factor theorem to determine and state whether $g (x)$ is a factor of $p (x)$ in each of the following cases:

p (x) = x^{3} + 3 x^{2} + 3 x + 1, g (x) = x + 2

p (x) = x^{3} + 3 x^{2} + 3 x + 1

x - 1

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