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Byju's Answer
Standard XII
Mathematics
Multinomial Expansion
x1+x2+...+xrn...
Question
(
x
1
+
x
2
+
.
.
.
+
x
r
)
n
=
∑
n
!
k
1
!
k
2
!
.
.
.
k
r
!
x
k
1
1
x
k
2
2
.
.
.
x
k
r
r
0
≤
k
1
,
k
2
,
.
.
.
,
k
r
≤
n
,
n
∈
N
;
k
1
+
k
2
+
.
.
.
+
k
r
=
n
A
True
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B
False
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Solution
The correct option is
A
True
Suggest Corrections
0
Similar questions
Q.
If
u
n
=
∫
x
n
√
a
x
2
+
2
b
x
+
c
d
x
then
a
u
n
+
1
+
2
b
u
n
+
c
u
n
−
1
=
√
a
x
2
+
2
b
x
+
c
x
n
+
k
1
n
+
k
1
−
a
u
n
+
k
3
n
+
k
2
−
b
u
n
+
k
4
n
+
k
2
then
Q.
If
m
,
n
are the roots of the equation
K
(
x
2
−
x
)
+
x
+
5
=
0.
If
K
1
and
K
2
are the two values of
K
for which the roots
m
,
n
are connected by the relation
m
n
+
n
m
=
4
5
.
Then the value of
K
1
K
2
+
K
2
K
1
is
Q.
The curves
x
2
a
2
+
k
1
+
y
2
b
2
+
k
1
=
1
,
x
2
a
2
+
k
2
+
y
2
b
2
+
k
2
=
1
where
k
1
≠
k
2
intersect at an angle
Q.
The angle between the curves
x
2
a
2
+
k
1
+
y
2
b
2
+
k
1
=
1
and
x
2
a
2
+
k
2
+
y
2
b
2
+
k
2
=
1
is
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