Question

$x^{10}÷(x^2\times x^3÷x)=x^m$, then $m=$

Answer 1

$x^{10}÷(x^2\times x^3÷x)=x^m$

$x^a\times x^b=x^{a+b}$

$\therefore x^2\times x^3=x^5$

$x^{10}÷(x^5÷x)=x^m$

$x^a÷x^b=x^{a-b}$

$\therefore x^5÷x^1=x^{5-1}=x^9$

$x^{10}÷x^4=x^{10}-x^4=x^6$

$\therefore x^6=x^m$

$\therefore m=6$