x–_______=15; when x2=6.
Step 1: Solve the given equation to find x
Let us solve,
x2=6⇒x=6×2⇒x=12
Step 2: Fill in the required blank
We have x–_=15
Now, let the required number be y, then
12-y=15⇒-y=15-12⇒-y=3∴y=-3
Thus, the blank is -3.
Write the quotient and remainder when we divide.
(15x2+x−6) by (3x+2)
Question 37
Fill in the blanks to make the statement true.
x - ................. = 15; when x2=6
6x + 3 = 15 is only trure when x = 2